IGCSE /Grade 10
Maths MCQ Based On Learning trigonometric ratios csc sec and cot
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IGCSE Grade 10 Maths Learning trigonometric ratios csc sec and cot
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If the cosine of theta is -5/13, then the sine of theta can be found using the Pythagorean identity. Therefore, the cotangent of theta is cosine divided by sine
We know that cosec θ = 1/sin θ and cot θ = 1/tan θ.
Substitute the values of cosec θ and cot θ into the given equation. Find a common denominator. Rearrange the equation. Factor out tan θ and solve for tan θ.
We are given cos α = -4/5, and we know α is in the fourth quadrant.
Step 1: Recall that cos α = adjacent/hypotenuse.
Step 2: Since α is in the fourth quadrant, both cos α and cot α are positive.
Step 3: Use the relationship between cos α and cot α
The cotangent (cot) of an acute angle in a right triangle is a ratio. It is the length of the adjacent leg (adj) divided by the length of the opposite leg (opp). The adjacent leg is the leg next to the specified angle and the opposite leg is the side across from the specified angle.
Memorise the basic formula of sec, cos and cot.
Inverse of tan
If the tangent is √3, then first find the value the sine of the angle.
The secant (sec) of an acute angle in a right triangle is a ratio. It is the length of the hypotenuse (hyp) divided by the length of the adjacent leg (adj). The hypotenuse is the side across from the right angle and the adjacent leg is the leg next to the specified angle.
We are given cos α = 4/7, Recall that cot α = 1/tan α. Use the Pythagorean identity for sine and cosine to find tan α. Use the relationship between cot α and tan α
Inverse of Cos
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