ICSE /Class 10
Maths MCQ Based On Quadratic equations in one variable
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ICSE Class 10 Maths Quadratic equations in one variable
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Put the value of variable in option
b^2 - 4ac > 0 So, 36 - 12m>0 we get m<3
use discriminant
Divide both the given equation.
Use the equation: \\(x^{2}+(x+1)^{2} = 145\\)
Put x=3
Discriminant = (-6)2 - 4(5) (8) = 36 - 160 < 0 So roots are imaginary
Standard form of Quadratic Equation
Let x and x + 1 be two consecutive numbers. Then,
\\(x^{2}+(x+1)^{2} = 181\\)
Solve the equation.
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