Common-Core/ Grade 9
Maths MCQ Based On Similar solid volume and surface area
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Common-Core Grade 9 - 9 Similar solid volume and surface area
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\\((\\frac{a}{b})^3 = \\frac{V_1}{V_2}\\)
\\((\\frac{a}{b})^3 = \\frac{V_1}{V_2}\\)
\\((\\frac{a}{b})^2 = \\frac{S_1}{S_2}\\)
\\((\\frac{a}{b})^3 = \\frac{V_1}{V_2}\\)
\\((\\frac{2}{5})^{2}=\\frac{8}{V}\\) Where V is the required volume
Let the required surface area of the cone be S.
\\(\\frac{4}{6}=\\frac{24}{S}\\)
Let the required surface area be S. Then, \\(\\)\\(2\\setminus 3=50\\setminus S\\)
Let the required volume be V. \\((\\frac{3}{6})^{2}= \\frac{18}{V}\\)
Let the required surface area be S. \\(\\frac{5}{8}=\\frac{30}{S}\\)
Let the required surface area be S. \\(\\frac{8}{10}=\\frac{48}{S}\\)
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