Common-Core/ Grade 8
Maths MCQ Based On Percent of change word problems
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Common-Core Grade 8 - 8 Percent of change word problems
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100% Of Original Amount+50% Of Original Amount=150% Of Original Amount Then Solve The Equation, Final Amount=150% Of Original Amount
Use: Percent Of Change= Amount Of Change/Original Amount
"20% more" means you should add 20% to the original amount. 100% of original amount + 20% of original amount =120% of the original amount.
100% Of Original Amount+25% Of Original Amount=125% Of Original Amount Then Solve The Equation, Final Amount=125% Of Original Amount
\\(Percent of change = \\frac{amount of change}{original amount}\\times 100\\)
Use: Percent Of Change= Amount Of Change/Original Amount
"83% more" means you should add 83% to the original amount.
100% of original amount + 83% of original amount =183% of the original amount
100% Of Original Amount+20% Of Original Amount=120% Of Original Amount Then Solve The Equation, Final Amount=120% Of Original Amount
100% Of Original Amount-50% Of Original Amount=50% Of Original Amount Then Solve The Equation, Final Amount=50% Of Original Amount
\\(Percent of change = \\frac{amount of change}{original amount}\\times 100\\)
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