Common-Core/ Grade 8
Maths MCQ Based On Find area of triangles
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Common-Core Grade 8 - 8 Find area of triangles
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The perimeter of a triangle is given by the formula P = a + b + c, where a, b, and c are the lengths of the sides.
You can find the area of a triangle with base b and height h using this formula A = 1/2x bxh.
since RS is the perpendicular bisector of side PQ, it is also the altitude of triangle PQR from vertex R to side PQ.
We know the area is\\( \\ {1 \\over 2}\\times base \\times height\\), now we just put the values of base and height in the formula.
Here the shape is a triangle so We can find the area using \\( \\ {1 \\over 2}\\times base \\times height\\).
First, change 4cm into m using 1m = 100cm then use the formula \\({1\\over2}\\times base\\times height\\)
We can use the formula for the area of a triangle given two sides and the included angle: A = (1/2)ab * sin©, where a and b are the lengths of the two sides and C is the measure of the included angle.
Since BD is the perpendicular bisector of side BC, it is also the altitude of triangle ABC from vertex B to side AC.
The area of a triangle is \\( \\ {1 \\over 2}\\times base \\times height\\), as we can see that the base is 4m and the height is 8m.
The area of the triangle is \\( \\ {1 \\over 2}\\times base \\times height\\). Here the height is 12km and the base is 4km.
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