Common-Core/ Grade 10
Maths MCQ Based On Surface area of pyramids and cones
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Common-Core Grade 10 - 10 Surface area of pyramids and cones
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Area=Pi R(R+Sqrt{H^{2}+R^{2}})
Surface area = \\( \\pi \\times r^{2}+\\pi \\times r \\times s\\)
Area=Pi R(R+Sqrt{H^{2}+R^{2}})
Use the formula of surface area of cone.
If b represents side of triangular base, a represents height of the base and s represents height of each lateral face then
Surface area = \\(\\frac{1}{2}\\times a\\times b + \\frac{3}{2} \\times b \\times s\\)
Area=Area Of Base+1/2 P S( P=Perimeter Of Base,S= Slant Height)
Find the side length of base using the formula \\(side^{2}\\)
Area=Pi R(R+Sqrt{H^{2}+R^{2}})
Area=Pi R(R+Sqrt{H^{2}+R^{2}})
The lace is tied along the perimeter of a circle.
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