CBSE /Class 10
Maths MCQ Based On Reducible equations in two variables
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CBSE Class 10 Maths Reducible equations in two variables
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Reduce the equation into the linear equation.
Let the cost of one pencil, eraser and sharpner be p, q and r. We have the equations,
\\(2p+5q+8r=47\\) and \\(3p+3q+7r=42\\) Multiply Eq. (2) by 2 and subtract Eq. (1) from Eq. (2), we have
\\(4p+q+6r=37\\) multiply this by 3 to get the answer.
Let the cost of one pencil, eraser and sharpner be p, q and r. We have the equations,
\\(2p+5q+8r=47\\) and \\(3p+3q+7r=42\\) Multiply Eq. (2) by 2 and subtract Eq. (1) from Eq. (2), we have
\\(4p+q+6r=37\\) multiply this by 3 to get the answer.
Use substitution method.
Use the conditions given in question to form linear equations.
Use substitution method.
Let the cost of one pencil, eraser and sharpner be p, q and r. We have the equations,
\\(2p+5q+8r=47\\) and \\(3p+3q+7r=42\\) Multiply Eq. (2) by 2 and subtract Eq. (1) from Eq. (2), we have
\\(4p+q+6r=37\\) multiply this by 3 to get the answer.
Use arbitrary values.
Reduce the equations into a linear form.
m & n are constants.
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